Physics · Simulator 018
Move a bar magnet through a coil and watch the voltmeter. Change the speed, the number of turns and the magnet's strength, or flip the magnet, to see Faraday's law: the voltage depends on how fast the flux changes, not on how much flux there is.
Magnetic flux through one loop is the field passing through it: Φ = ∫ B·dA. Faraday's law says a changing flux induces an EMF in a coil of N turns:
ε = −N · dΦ/dt
The minus sign is Lenz's law: the induced current opposes the change. As the magnet's north pole approaches, flux increases and the induced current makes the near face of the coil a north pole that pushes back. As the magnet leaves, the sign reverses.
The model treats the magnet as a magnetic dipole on the coil's axis. The flux through a loop of radius a at axial distance z is Φ = μ₀ m a² / (2(a² + z²)^{3/2}). The EMF follows from the chain rule dΦ/dt = (dΦ/dz)·v.
Idealised: point dipole, thin coil, no current-induced forces on the magnet, and an open-circuit voltmeter. Numbers are illustrative, of school-lab magnitude.
You double the number of turns and halve the speed. What happens to the peak EMF and to the total flux change during the pass?
Peak EMF ∝ N·v, so it is unchanged (2 × ½ = 1). The total change of NΦ doubles, because the flux per turn is the same and there are twice as many turns. The pulses are now twice as long, at the same height.